11. Container With Most Water
Given n non-negative integers a1, a2, ..., an , where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.
Note: You may not slant the container and n is at least 2.

The above vertical lines are represented by array [1,8,6,2,5,4,8,3,7]. In this case, the max area of water (blue section) the container can contain is 49.
Example:
Input: [1,8,6,2,5,4,8,3,7]
Output: 49
解题要点:
两个指针,一个左一个右。记录最大水量min(左,右) * 宽,如果左高度小于右,则左+=1,反之则右-=1。
class Solution(object):
def maxArea(self, height):
"""
:type height: List[int]
:rtype: int
"""
l = 0
r = len(height) - 1
maxWater = 0
while l < r:
maxWater = max(maxWater, min(height[l], height[r]) * (r - l))
if height[l] < height[r]:
l += 1
else:
r -= 1
return maxWater
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