232. Implement Queue using Stacks
Implement the following operations of a queue using stacks.
push(x) -- Push element x to the back of queue.
pop() -- Removes the element from in front of queue.
peek() -- Get the front element.
empty() -- Return whether the queue is empty.
Example:
MyQueue queue = new MyQueue();
queue.push(1);
queue.push(2);
queue.peek(); // returns 1
queue.pop(); // returns 1
queue.empty(); // returns false
Notes:
You must use only standard operations of a stack -- which means only
push to top
,peek/pop from top
,size
, andis empty
operations are valid.Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack.
You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).
解题要点:
运用stack的特性,先进后出,思路为把s1全部倾倒在s2里,把数加到s2顶端,然后再倾倒在s1里。这时,s1里的顺序为倒叙,因此可以实现queue的方法。
class MyQueue {
Stack<Integer> s1 = null;
Stack<Integer> s2 = null;
int size;
boolean done;
/** Initialize your data structure here. */
public MyQueue() {
s1 = new Stack<>();
s2 = new Stack<>();
size = 0;
}
/** Push element x to the back of queue. */
public void push(int x) {
while(s1.size() > 0){
// 转到s2
s2.push(s1.pop());
}
s2.push(x);
while(s2.size() > 0){
s1.push(s2.pop());
}
size++;
}
/** Removes the element from in front of queue and returns that element. */
public int pop() {
size--;
return s1.pop();
}
/** Get the front element. */
public int peek() {
return s1.peek();
}
/** Returns whether the queue is empty. */
public boolean empty() {
return size == 0;
}
}
/**
* Your MyQueue object will be instantiated and called as such:
* MyQueue obj = new MyQueue();
* obj.push(x);
* int param_2 = obj.pop();
* int param_3 = obj.peek();
* boolean param_4 = obj.empty();
*/
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