359. Logger Rate Limiter
Design a logger system that receive stream of messages along with its timestamps, each message should be printed if and only if it is not printed in the last 10 seconds.
Given a message and a timestamp (in seconds granularity), return true if the message should be printed in the given timestamp, otherwise returns false.
It is possible that several messages arrive roughly at the same time.
Example:
Logger logger = new Logger();
// logging string "foo" at timestamp 1
logger.shouldPrintMessage(1, "foo"); returns true;
// logging string "bar" at timestamp 2
logger.shouldPrintMessage(2,"bar"); returns true;
// logging string "foo" at timestamp 3
logger.shouldPrintMessage(3,"foo"); returns false;
// logging string "bar" at timestamp 8
logger.shouldPrintMessage(8,"bar"); returns false;
// logging string "foo" at timestamp 10
logger.shouldPrintMessage(10,"foo"); returns false;
// logging string "foo" at timestamp 11
logger.shouldPrintMessage(11,"foo"); returns true;
解题要点:
创建一个新dictionary,在有相同key时,比较两个的时间戳,如果两者之差小于10则不加进dict里,如两者等于或大于时,更新key的值为新的时间戳。
class Logger(object):
def __init__(self):
"""
Initialize your data structure here.
"""
self.myDict = {}
def shouldPrintMessage(self, timestamp, message):
"""
Returns true if the message should be printed in the given timestamp, otherwise returns false.
If this method returns false, the message will not be printed.
The timestamp is in seconds granularity.
:type timestamp: int
:type message: str
:rtype: bool
"""
if message in self.myDict:
timelapse = timestamp - self.myDict[message]
if timelapse < 10:
return False
else:
self.myDict[message] = timestamp
else:
self.myDict[message] = timestamp
return True
# Your Logger object will be instantiated and called as such:
# obj = Logger()
# param_1 = obj.shouldPrintMessage(timestamp,message)
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