206. Reverse Linked List
Input: 1->2->3->4->5->NULL
Output: 5->4->3->2->1->NULL解题要点:
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
class Solution {
public ListNode reverseList(ListNode head) {
ListNode prev = null;
ListNode curr = head;
while(curr != null){
ListNode temp = curr.next;
curr.next = prev;
prev = curr;
curr = temp;
}
return prev;
}
}Last updated